25悬关

#include<bits/stdc++.h>

using namespace std;

int main(){
    long long x,m;
    cin >> x >> m;
    string temp = "";
    while(x > 0){
        long long a;
        a = x;
        a = a % m;      //取余数
        long long b = a;
        string ans = to_string(a);      //转换成string类型
        temp = ans + temp;
        x = x / 2;        //取出下次循环的x
    }
    cout << temp << endl;
    return 0;
}