52分求调

#include<bits/stdc++.h>
using namespace std;

long long n,a[200002],m[200002],suma=1,sumb=1,ans=0;

int main(){
	cin>>n;
	for(int i=1;i<=n;i++){
		cin>>m[i];
	}
	for(int i=1;i<=n;i++){
		cin>>a[i];
	}
	for(int i=1;i<=n;i++){
		suma=1;
		sumb=1;
		for(int j=1;j<=n;j++){
			int num=0;
			if(suma==0&&sumb==0)break;
			if(j!=i){
				if(m[i]-a[i]<m[j]-a[j])num+=1;
				if(m[i]-a[i]<a[j]-1)num+=1;
				if(m[i]-a[i]==m[j]-a[j]&&i<j)num+=1;
				if(m[i]-a[i]==a[j]-1&&i<j)num+=1;
				suma*=num;
				num=0;
				if(a[i]-1<m[j]-a[j])num+=1;
				if(a[i]-1<a[j]-1)num+=1;
				if(a[i]-1==m[j]-a[j]&&i<j)num+=1;
				if(a[i]-1==a[j]-1&&i<j)num+=1;
				sumb*=num;
			}
		}
		ans=ans+(m[i]-a[i])*suma+(a[i]-1)*sumb;
	}
	cout<<(ans+1)%(10*10*10*10*10*10*10*10*10+7);
}