80分求调

#include <iostream>
using namespace std;

int main()
{
    long long N;
    cin >> N;
    if (N < 0)
    {
        cout << "-";
        N = -N;
    }
    if (N % 10 == 0)
        N = N / 10;
    while (N != 0)
    {
        cout << N % 10;
        N /= 10;
    }

    return 0;
}