求调

#include <bits/stdc++.h>
using namespace std;
int n,m,a[1000001];
int main() {
	cin >> n;
	for (int i = 1;i <= n;i++) cin >> a[i];
	cin >> m;
	while (m--){
		long long l,r,cnt = 0;
		cin >> l >> r;
		for (int i = l;i <= r;i++) cnt += a[i];
		cout << cnt << "\n";
	}
	return 0;
}