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线段树求挑交
P1198[JSOI2008] 最大数参与者 2已保存回复 2
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- @lzkw86m0
- 此快照首次捕获于
- 2024/08/08 14:24 2 年前
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- 2024/08/08 15:19 2 年前
线段树只过了最后一个点
其他点全部RE
求调
CPP#include <iostream>
using namespace std;
#define ll long long
const int N = 2e5 + 10;
ll n, D;
ll a[N];
ll tree[N << 2];
ll tag[N << 2];
ll ls(ll p) {return p << 1; }
ll rs(ll p) {return p << 1 | 1; }
ll max(ll a, ll b) {
return a > b ? a : b;
}
void push_up(ll p) {
tree[p] = max(tree[ls(p)], tree[rs(p)]);
}
void addtag(ll p, ll pl, ll pr, ll d) {
tag[p] += d;
tree[p] += d * (pr - pl + 1);
}
void push_down(ll p, ll pl, ll pr) {
if(tag[p]){
ll mid = (pl + pr) >> 1;
addtag(ls(p), pl, mid, tag[p]);
addtag(rs(p), mid + 1, pr, tag[p]);
tag[p] = 0;
}
}
void update(ll L, ll p, ll pl, ll pr, ll d) {
if(pl == pr){
tree[p] = d;
return ;
}
ll mid = (pl + pr) >> 1;
if(L <= mid) update(L, ls(p), pl, mid, d);
if(L > mid) update(L, rs(p), mid + 1, pr, d);
tree[p] = max(tree[ls(p)], tree[rs(p)]) % D;
}
ll query(ll L, ll R, ll p, ll pl, ll pr) {
if(pl >= L && pr >= R) return tree[p];
push_down(p, pl, pr);
ll res1 = 0, res2 = 0;
ll mid = (pl + pr) >> 1;
if(L <= mid) res1 = query(L, R, ls(p), pl, mid);
if(R > mid) res2 = query(L, R, rs(p), mid + 1, pr);
return max(res1, res2);
}
int main(){
int cnt = 0;
int t = 0;
cin >> n >> D;
for(int i = 0 ; i < n ; i ++){
char ch;
ll x;
cin >> ch >> x;
if(ch == 'A') {
++cnt;
update(cnt, 1, 1, n, (x + t) % D);
}
if(ch == 'Q') {
if(x == 0) t = 0;
else t = query(cnt - x + 1, cnt, 1, 1, n) % D;
cout << t << '\n';
}
}
return 0;
}
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