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WA on 4 求助
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- 此快照首次捕获于
- 2024/08/06 17:55 2 年前
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代码清晰!
CPP#include<cstdio>
#include<algorithm>
#include<cmath>
#include<iostream>
#include<set>
#include<vector>
#include<queue>
#include<stack>
#include<cstring>
#include<cstdlib>
#include<map>
#include<ctime>
#include<unordered_map>
#define rep(i,a,b) for(register int i=a;i<=b;++i)
#define rev(i,a,b) for(register int i=a;i>=b;--i)
#define gra(i,u) for(register int i=head[u];i;i=edge[i].nxt)
#define Clear(a) memset(a,0,sizeof(a))
#define yes puts("YES")
#define no puts("NO")
using namespace std;
typedef long long ll;
const int INF(1e9+10);
const ll LLINF(1e18+10);
inline int read()
{
int s=0,w=1;
char ch=getchar();
while(ch<'0'||ch>'9'){if(ch=='-')w=-1;ch=getchar();}
while(ch>='0'&&ch<='9')s=s*10+(ch-'0'),ch=getchar();
return s*w;
}
template<typename T>
inline T Min(T x,T y){return x<y?x:y;}
template<typename T>
inline T Max(T x,T y){return x>y?x:y;}
template<typename T>
inline void Swap(T&x,T&y){T t=x;x=y;y=t;return;}
template<typename T>
inline T Abs(T x){return x<0?-x:x;}
const int MOD(1e9+7);
template<typename T>
inline T add(T x){return x;}
template<typename T,typename... types>
inline T add(T x,types... y){T z=add<T>(y...);return x+z>=MOD?x+z-MOD:x+z;}
template<typename T>
inline T mul(T x){return x;}
template<typename T,typename... types>
inline T mul(T x,types... y){return (ll)x*mul<T>(y...)%MOD;}
inline int sub(int x,int y){return add(x-y,MOD);}
const int MAXN(1e5+10);
int n,m,a[MAXN];
vector<int>G[MAXN];
int root(1);
int dfn[MAXN],rk[MAXN],tot;
int siz[MAXN],par[MAXN][23],son[MAXN],top[MAXN],dep[MAXN];
inline void dfs1(int u,int fa)
{
par[u][0]=fa,dep[u]=dep[fa]+1,siz[u]=1;
rep(i,1,20) par[u][i]=par[par[u][i-1]][i-1];
for(auto v:G[u]) if(v!=fa)
{
dfs1(v,u);
siz[u]+=siz[v];
if(siz[v]>siz[son[u]]) son[u]=v;
}
return;
}
inline void dfs2(int u,int topf)
{
top[u]=topf;
dfn[u]=++tot;
rk[tot]=u;
if(son[u]) dfs2(son[u],topf);
for(auto v:G[u]) if(v!=par[u][0]&&v!=son[u]) dfs2(v,v);
return;
}
struct Segment_Tree
{
ll tree[MAXN<<2],tag[MAXN<<2];
inline int lc(int p){return p<<1;}
inline int rc(int p){return p<<1|1;}
inline void push_up(int u)
{
tree[u]=tree[lc(u)]+tree[rc(u)];
return;
}
inline void build(int u,int l,int r)
{
if(l==r)
{
tree[u]=a[rk[l]];
return;
}
int mid=(l+r)>>1;
build(lc(u),l,mid),build(rc(u),mid+1,r);
push_up(u);
return;
}
inline void lazy_tag(int u,int l,int r,int k)
{
tree[u]+=1ll*(r-l+1)*k;
tag[u]+=k;
return;
}
inline void push_down(int u,int l,int r)
{
int mid=(l+r)>>1;
lazy_tag(lc(u),l,mid,tag[u]);
lazy_tag(rc(u),mid+1,r,tag[u]);
tag[u]=0;
}
inline void update(int u,int l,int r,int ln,int rn,int k)
{
if(ln>rn) return;
if(ln<=l&&r<=rn)
{
lazy_tag(u,l,r,k);
return;
}
push_down(u,l,r);
int mid=(l+r)>>1;
if(ln<=mid) update(lc(u),l,mid,ln,rn,k);
if(rn>mid) update(rc(u),mid+1,r,ln,rn,k);
push_up(u);
return;
}
inline ll query(int u,int l,int r,int ln,int rn)
{
if(ln<=l&&r<=rn) return tree[u];
push_down(u,l,r);
int mid=(l+r)>>1;
ll res=0;
if(ln<=mid) res+=query(lc(u),l,mid,ln,rn);
if(rn>mid) res+=query(rc(u),mid+1,r,ln,rn);
return res;
}
};
Segment_Tree seg;
inline int LCA(int x,int y)
{
if(dep[x]<dep[y]) Swap(x,y);
rev(k,20,0) if(dep[par[x][k]]>=dep[y]) x=par[x][k];
if(x==y) return x;
rev(k,20,0) if(par[x][k]!=par[y][k]) x=par[x][k],y=par[y][k];
return par[x][0];
}
inline bool in(int x)
{
if(dfn[root]<=dfn[x]&&dfn[x]<=dfn[root]+siz[root]-1) return true;
return false;
}
inline void update(int x,int k)
{
if(x==root) seg.update(1,1,n,1,n,k);
else if(dfn[x]<=dfn[root]&&dfn[root]<=dfn[x]+siz[x]-1)
{
int y=root;
rev(k,20,0) if(dep[par[y][k]]-1>=dep[x]) y=par[y][k];
int l=dfn[y],r=dfn[y]+siz[y]-1;
seg.update(1,1,n,1,l-1,k),seg.update(1,1,n,r+1,n,k);
}
else seg.update(1,1,n,dfn[x],dfn[x]+siz[x]-1,k);
return;
}
inline int find(int x,int y)
{
if(in(x)&&in(y)) return LCA(x,y);
if(in(x)||in(y)) return root;
int p=LCA(x,root),q=LCA(y,root);
if(dep[p]>=dep[q]) return p;
return q;
}
inline ll query(int x)
{
if(x==root) return seg.query(1,1,n,1,n);
if(dfn[x]<=dfn[root]&&dfn[root]<=dfn[x]+siz[x]-1)
{
int y=root;
rev(k,20,0) if(dep[par[y][k]]-1>=dep[x]) y=par[y][k];
return seg.query(1,1,n,1,n)-seg.query(1,1,n,dfn[y],dfn[y]+siz[y]-1);
}
return seg.query(1,1,n,dfn[x],dfn[x]+siz[x]-1);
}
int main()
{
n=read(),m=read();
rep(i,1,n) a[i]=read();
rep(i,2,n)
{
int u=read(),v=read();
G[u].push_back(v),G[v].push_back(u);
}
dfs1(1,0);
dfs2(1,1);
seg.build(1,1,n);
while(m--)
{
int opt=read(),u=read();
if(opt==1) root=u;
else if(opt==2)
{
int v=read(),x=read();
int lca=find(u,v);
update(lca,x);
}
else printf("%lld\n",query(u));
}
return 0;
}
/* things to check
1. int overflow or long long memory need
2. recursion/array/binary search/dp/loop bounds
3. precision
4. special cases(n=1,bounds)
5. delete debug statements
6. initialize(especially multi-tests)
7. = or == , n or m ,++ or -- , i or j , > or >= , < or <=
8. keep it simple and stupid
9. do not delete, use // instead
10. operator priority
11. is there anything extra to output?
12. ...
*/
/* something to think about
1. greedy? dp? searching? dp with matrix/ segment tree? binary search?
2. If contains "not", why not ?????? or few affect?
*/
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