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求调线段树 抓个好心人

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@lxeso5gc
此快照首次捕获于
2024/06/14 22:39
2 年前
此快照最后确认于
2024/06/15 10:50
2 年前
查看原帖
CPP
#include <bits/stdc++.h>
#define int long long
using namespace std;
const int N = 1e6 + 10;
const int M = 1e6;
struct node {
    int sum, maxx;
}tree[N << 2];
int a[N], t[N];
void build(int i, int l, int r) {
    if (l == r) {
        tree[i].sum = a[l];
        tree[i].maxx = a[l];
        return;
    }
    int mid = (l + r) / 2;
    build(i << 1, l, mid);
    build(i << 1 | 1, mid + 1, r);
    tree[i].sum = tree[i << 1].sum + tree[i << 1 | 1].sum;
    tree[i].maxx = max (tree[i << 1].maxx, tree[i << 1 | 1].maxx);
    return;
}
void update (int i, int lx, int rx, int x, int k) {
	if (tree[i].maxx <= 2) {
		return;
	}
    if (lx == rx) {
    	a[lx] = t[a[lx]];
        tree[i].sum = tree[i].maxx = a[lx];
        return;
    }
    int mid = (lx + rx) >> 1;
    if (x <= mid) {
        update(i << 1, lx, mid, x, k);
    } else if (x > mid) {
        update(i << 1 | 1, mid + 1, rx, x, k);
    } 
    tree[i].sum = tree[i << 1].sum + tree[i << 1 | 1].sum;
    tree[i].maxx = max (tree[i << 1].maxx, tree[i << 1 | 1].maxx);
}
int query(int i, int lx, int rx, int l, int r) {
    if (l <= lx && rx <= r) {
        return tree[i].sum;
    }
    int mid = (lx + rx) >> 1;
    int ans = 0;
    if (l <= mid) {
        ans += query(i << 1, lx, mid, l, r);
    }
    if (r > mid) {
        ans += query(i << 1 | 1, mid + 1, rx, l, r);
    }
 	return ans;
}
signed main () {
    int n, m;
    cin >> n >> m;
    for (int i = 1; i <= n; i ++ ) {
        cin >> a[i];
    }
    build(1, 1, n); 
    for (int i = 2; i <= M; i ++ ) {
		for (int j = i; j <= M; j += i) {
			t[j] ++;
		}
		t[i] ++;
	}
    while (m --) {
		int op, x, y;
		cin >> op >> x >> y;
		if (op == 1) {
			update (1, 1, n, x, y);
		} else {
			cout << query (1, 1, n, x, y) << "\n";
		}
	}
}
感激不尽!!!

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