与解答基本一致，为何不对求调

#include <iostream> 
#include<cstdio>
using namespace std ;
int main()
{
    int n , k = 0 ;
    cin >> n ;
    cin >> k ;
    double aveA , aveB , sumA , sumB  ;
    int numA ,numB = 0 ;
    for(int i = 1 ; i <= n; i++)
    {
        if( i % k == 0 )
        {
            sumA += i ;
            numA ++ ;
        }
        else
        {
            sumB += i ;
            numB ++ ;
        }
    }
    aveA =sumA / numA ;
    aveB = sumB / numB ;
    printf("%.1lf %.1lf",aveA,aveB) ;
    return 0;
}