20分代码求调

#include<bits/stdc++.h>
using namespace std;
unsigned long long a[100005];
int main(){
	int n, k;
	unsigned long long ans = 0;
	scanf("%d%d",&n, &k);
	if(k == 1){
		cout << 1;
		return 0;
	}else{
		a[1] = 1, a[2] = 2;
		for(int i = 3; i <= n; i++){
			ans = 0;
			for(int j = i-1; j >= max(1, i-k); j--){
				ans += a[j]%100003;
				//cout << a[j] << " ";
				//cout << ans << " ";
			}
			//cout << "\n";
			a[i] = ans;
		}
		cout << a[n]%100003;
	}
	
	return 0;
}