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CF754BIlya and tic-tac-toe game参与者 4已保存回复 6
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- 2023/10/27 23:44 2 年前
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- 2023/10/27 23:44 2 年前
CPP
#include <iostream>
#include <cmath>
#include <cstring>
#include <string>
#include <set>
#include <algorithm>
#define ll long long
#define INF 0x3f3f3f3f
using namespace std;
char g[10][10];
int vis[10][10];
int n = 4;
int flag = 0;
void dfs(int x, int y) {
if(x > 4 || y > 4 || x < 1 || y < 1)
return;
if(y <= 2 && (g[x][y+1] == 'x' && g[x][y+2] == 'x') ||
(g[x][y+1] == 'x' && g[x][y+2] == '.') ||
(g[x][y+1] == '.' && g[x][y+2] == 'x'))
flag = 1;
if(y >= 3 && (g[x][y-1] == 'x' && g[x][y-2] == 'x') ||
(g[x][y-1] == 'x' && g[x][y-2] == '.') ||
(g[x][y-1] == '.' && g[x][y-2] == 'x'))
flag = 1;
if(x <= 2 && (g[x+1][y] == 'x' && g[x+2][y] == 'x') ||
(g[x+1][y] == 'x' && g[x+2][y] == '.') ||
(g[x+1][y] == '.' && g[x+2][y] == 'x'))
flag = 1;
if(x >= 3 && (g[x-1][y] == 'x' && g[x-2][y] == 'x') ||
(g[x-1][y] == 'x' && g[x-2][y] == '.') ||
(g[x-1][y] == '.' && g[x-2][y] == 'x'))
flag = 1;
//对角线
if(x <= 2 && y <= 2 && (g[x+1][y+1] == 'x' && g[x+2][y+2] == 'x') ||
(g[x+1][y+1] == 'x' && g[x+2][y+2] == '.') ||
(g[x+1][y+1] == '.' && g[x+2][y+2] == 'x'))
flag = 1;
if(x >= 3 && y >= 3 && (g[x-1][y-1] == 'x' && g[x-2][y-2] == 'x') ||
(g[x-1][y-1] == 'x' && g[x-2][y-2] == '.') ||
(g[x-1][y-1] == '.' && g[x-2][y-2] == 'x'))
flag = 1;
if(x <= 2 && y >= 3 && (g[x+1][y-1] == 'x' && g[x+2][y-2] == 'x') ||
(g[x+1][y-1] == 'x' && g[x+2][y-2] == '.') ||
(g[x+1][y-1] == '.' && g[x+2][y-2] == 'x'))
flag = 1;
}
int main() {
ios::sync_with_stdio(false); cin.tie(0);
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= n; ++j) {
cin >> g[i][j];
}
}
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= n; ++j) {
if(g[i][j] == 'x')
dfs(i,j);
if(flag) {
cout << "YES";
return 0;
}
}
}
cout << "NO";
return 0;
}
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