40求调 额额额

#include<bits/stdc++.h>
using namespace std;
int n,he;
double ans;
int n1[10005];
int main(){
    cin>>n;
    for(int i=1;i<=n;i++){
        cin>>n1[i];
        he+=n1[i];
    }
    
    ans=he;
    cout<<ans<<' '<<setprecision(5)<<fixed<<ans/n<<endl;
    return 0;
}