求救，为什么题目给的样例可以通过但是全RE啊

#include<bits/stdc++.h>
using namespace std;

int main(){
    int n;
    cin>>n;
    string str;
    cin>>str;
    cin.ignore();
    for(int i=0;i<n;i++)
    {
        string temp;
        getline(cin,temp);
        char choice=temp[0];
        if(choice=='1')
        {
            string str1=temp.substr(2);
            str+=str1;
            cout<<str<<endl;
        }
        else if(choice=='2')
        {
            string str1=temp.substr(2);
            size_t kongge_pos=str1.find(' ');
            string str_num1=str1.substr(0,kongge_pos);
            string str_num2=str1.substr(kongge_pos+1);
            int num1=0,num2=0;
            for(int i=0;i<str_num1.size();i++)
            {
                num1+=(str_num1[i]-'0')*pow(10,str_num1.size()-i-1);
            }
            for(int i=0;i<str_num2.size();i++)
            {
                num2+=(str_num2[i]-'0')*pow(10,str_num2.size()-i-1);
            }
            str=str.substr(num1,num2);
            cout<<str<<endl;
        }
        else if(choice=='3')
        {
            string str1=temp.substr(2);
            size_t kongge_pos=str1.find(' ');
            string str_num=str1.substr(0,kongge_pos);
            string word=str1.substr(kongge_pos+1);
            int num=0;
            for(int i=0;i<str_num.size();i++)
            {
                num+=(str_num[i]-'0')*pow(10,str_num.size()-i-1);
            }
            string word1=str.substr(0,num);
            string word2=str.substr(num);
            str=word1+word+word2;
            cout<<str<<endl;
        }
        else
        {
            string word=temp.substr(2);
            size_t pos=str.find(word);
            if(pos!=string::npos)
            {
                cout<<pos<<endl;
            }
            else
            {
                cout<<-1<<endl;
            }
        }
    }
    return 0;
}