对于c语言初学者的简单方案

#include <stdio.h>
int main()
{
    int a, b, c, d;
    scanf("%d %d %d %d", &a, &b, &c, &d);
    
    // 将时间都转换成分钟
    int start = a * 60 + b;
    int end   = c * 60 + d;
    
    int diff = end - start;        // 总分钟差
    int e = diff / 60;            // 小时
    int f = diff % 60;            // 分钟（一定小于60）
    
    printf("%d %d", e, f);
    return 0;
}