社区讨论
TLE 求调
UVA10140Prime Distance参与者 2已保存回复 2
讨论操作
快速查看讨论及其快照的属性,并进行相关操作。
- 当前回复
- 2 条
- 当前快照
- 1 份
- 快照标识符
- @mlhw8h7u
- 此快照首次捕获于
- 2026/02/11 18:35 上周
- 此快照最后确认于
- 2026/02/11 19:25 上周
CPP
#include<bits/stdc++.h>
#define int long long
#define endl '\n'
using namespace std;
const int maxn = 1e6 + 5;
int l, r, top, q[maxn];
bool vis[maxn], isp[maxn];
void Euler(int n)
{
isp[0] = false;
isp[1] = false;
for (int i = 2; i <= n; ++ i)
{
if (isp[i] == false)
{
continue;
}
for (int j = i; i * j <= n; ++ j)
{
isp[i * j] = false;
}
}
return;
}
signed main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
fill(isp, isp + maxn, true);
Euler(maxn - 2);
while (cin >> l >> r)
{
top = 0;
memset(q, 0, sizeof q);
memset(vis, 0, sizeof vis);
for (int i = 2; i * i <= r; ++ i)
{
for (int j = l; j <= r; ++ j)
{
if (j % i == 0 && i != j)
{
vis[j - l + 1] = true;
}
}
}
for (int i = 1; i <= r - l + 1; ++ i)
{
if (vis[i] == false)
{
q[++ top] = i + l - 1;
}
}
if (top < 2)
{
cout << "There are no adjacent primes." << endl;
continue;
}
int minn = INT_MAX, maxx = INT_MIN;
bool appi = false, appa = false;
for (int i = 2; i <= top; ++ i)
{
minn = min(minn, q[i] - q[i - 1]);
maxx = max(maxx, q[i] - q[i - 1]);
}
for (int i = 2; i <= top; ++ i)
{
if (appi == false && (q[i] - q[i - 1]) == minn)
{
appi = true;
cout << q[i - 1] << "," << q[i] << " are closest, ";
break;
}
}
for (int i = 2; i <= top; ++ i)
{
if (appa == false && (q[i] - q[i - 1]) == maxx)
{
appa = true;
cout << q[i - 1] << "," << q[i] << " are most distant." << endl;
break;
}
}
}
return 0;
}
回复
共 2 条回复,欢迎继续交流。
正在加载回复...