一个if的AC

12345678910111213141516171819202122//main.cpp
include <iostream>  

using namespace std;  

int T, a, b, c, d;  

int main(void)  
{  
    cin >> T;  
    for(int i = 0;i < T;i++)  
    {  
        cin >> a >> b >> c >> d;  
        if((a + b == a + c && b + d == c + d && b + d == a + b) || (a + b == a + d && b + c == d + c && b + c == a + b) || (a + c == a + d && c + b == d + b && a + c == c + b))
        {
            cout << "Yes" << endl;
        }
        else
        {
            cout << "No" << endl;
        }
    }
}