0分求调!

#include<bits/stdc++.h>
using namespace std;
int main (){
	int n;
	double a[10000];
	int sum=0,sum1=0;
	int m=0,n1=1000000;
	cin >> n;
	for(int i=1; i<=n;i++){
      cin >> a[i];
      if(m<a[i]){
      	m = a[i];
	  }
	  if(n1>a[i]){
	  	n1 =a[i];
	  }
      
	}
	for(int i=1;i<=n;i++){
		if(a[i] == m || a[i] ==n){
			continue;
		}
		sum += a[i];
	}
	for(int i=1;i<=n;i++){
		sum1 += a[i];
	}
	printf("%.2lf", sum1*1.0/(n-2));
	double ans = abs(sum1 *1.0 /n - (sum *1.0 /(n-2)));
	printf("%.2lf", ans);
	return 0;
}