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P14635[NOIP2025] 糖果店参与者 2已保存回复 5

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@mikg9y3c
此快照首次捕获于
2025/11/29 23:32
3 个月前
此快照最后确认于
2025/12/01 21:25
3 个月前
查看原帖
思路二分重复选择糖果的重复数量
CPP
#include <bits/stdc++.h>
using namespace std;

#define int long long

int n, m;
array<int, 2> a[100009];
int d[100009];
int minn = 0x7f7f7f7f7f7f7f7f;

inline int check(int x) {
	int i = upper_bound(d, d + n + 1, m - x * minn) - d - 1;
	return x * 2 + i;
}

signed main() {

	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);

	cin >> n >> m;
	for(int i = 1; i <= n ;i++){
		cin >> a[i][0] >> a[i][1];
		if(a[i][0] + a[i][1] < minn) minn = a[i][0] + a[i][1];
	}
	sort(a + 1, a + n + 1);
	for(int i = 1; i <= n ;i++) {
		d[i] = d[i - 1] + a[i][0];
		// cout << d[i] << " ";
	}
	// cout << "\n";
	int l = 0, r = m / minn, maxn = check(r);
	while(l < r) {
		int mid = l + r >> 1;
		if(check(mid) >= maxn) {
			r = mid;
			maxn = check(mid);
		} else {
			l = mid + 1;
		}
	}
	// cout << l << " " << minn << "\n";
	// cout << m - l * minn << " " << i << "\n";
	cout << maxn << "\n";
	return 0;

}

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