TLE求调，必关T^T

#include<iostream>
int ys(int a){
	int ans=0;
	for(int i=1;i<=a;i++)if(a%i==0)ans++;
	return ans;
}
int sumy[1000005];
int main(){
	int n;
	std::cin>>n;
	for(int i=1;i<=n;i++)sumy[i]=sumy[i-1]+ys(i);
	std::cout<<sumy[n];
	return 0;
}