社区讨论
求调玄关被hack
P10113[GESP202312 八级] 大量的工作沟通参与者 3已保存回复 3
讨论操作
快速查看讨论及其快照的属性,并进行相关操作。
- 当前回复
- 3 条
- 当前快照
- 1 份
- 快照标识符
- @mi0vc9m9
- 此快照首次捕获于
- 2025/11/16 06:38 4 个月前
- 此快照最后确认于
- 2025/11/17 09:12 4 个月前
CPP
#include <bits/stdc++.h>
#define IAKIOI ios::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);
#define UPB(x, y, z) upper_bound(x + 1, x + y + 1, z) - x
#define LWB(x, y, z) lower_bound(x + 1, x + y + 1, z) - x
#define rep(i, l, r) for (int i = l; i <= r; i++)
#define pre(i, r, l) for (int i = r; i >= l; i--)
#define UNIQUE(x, y) unique(x + 1, x + y + 1)
#define SORT(x, y) sort(x + 1,x + y + 1)
#define pf push_front
#define pb push_back
#define IT iterator
#define lowbit(x) x & (-x)
#define re read()
#define wr(n) write(n)
#define sp putchar(' ')
#define endl puts("")
const int N = 1e5 + 10, INF = 1e9;
const double ecnts = 1e-6;
using namespace std;
#define int long long
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<int, pair<int, int> > piii;
typedef double db;
int read() {
int f = 1, y = 0;
char c = getchar();
while (!isdigit(c)) {
if (c == '-') f = -1;
c = getchar();
}
while (isdigit(c)) {
y = y * 10 + c - '0';
c = getchar();
}
return y * f;
}
void write(int x) {
if(x < 0) putchar('-'), x = -x;
if(x > 9) write(x / 10);
putchar(x % 10 + '0');
}
inline int max(int x, int y) {return x > y ? x : y;}
inline int min(int x, int y) {return x < y ? x : y;}
inline void swap(int &x, int &y) {int t = x;x = y, y = t;}
inline int pow(int x, int y) {
int ans = 1;
while (y) {
if (y & 1) ans *= x;
x *= x, y = y >> 1;
}
return ans;
}
int n, q;
int fa[N][25];
int depth[N];
int maxn[N];
vector<int> g[N];
void dfs(int u) {
//maxn[v]->u
for (auto v : g[u]) {
maxn[v] = max(maxn[v], maxn[u]);
dfs(v);
}
}
int lca(int x, int y) {
if (depth[x] > depth[y]) swap(x, y);
pre(i, 20, 0) if (depth[fa[y][i]] >= depth[x]) y = fa[y][i];
if (x == y) return x;
pre(i, 20, 0) if (fa[x][i] != fa[y][i]) x = fa[x][i], y = fa[y][i];
return fa[x][0];
}
signed main() {
IAKIOI
n = re;
iota(maxn, maxn + n + 1, 0);
depth[0] = 0;
rep(i, 1, n - 1) fa[i][0] = re, depth[i] = depth[fa[i][0]] + 1, g[fa[i][0]].push_back(i);
rep(i, 1, 20) rep(j, 0, n - 1) fa[j][i] = fa[fa[j][i - 1]][i - 1];
dfs(0);
// rep(i, 0, n - 1) wr(maxn[i]), sp;
// endl;
q = re;
while (q--) {
int k = re - 1;
int x = re;
while (k--) {
int y = re;
x = lca(x, y);
}
wr(maxn[x]), endl;
}
}
回复
共 3 条回复,欢迎继续交流。
正在加载回复...