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P2433【深基1-2】小学数学 N 合一参与者 3已保存回复 9

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@mhj1zryf
此快照首次捕获于
2025/11/03 19:25
4 个月前
此快照最后确认于
2025/11/03 19:25
4 个月前
查看原帖
CPP
#include<bits/stdc++.h>
using namespace std;
int main(){
    cout << "I love luogu!" << endl;
    cout << 2 + 4 << " " << 10 - 2 - 4 << endl;
    cout << 14 / 4 << endl;
    cout << 14 - 14 % 4 << endl;
    cout << 14 % 4 << endl;
    double result = 500.0 / 3;
    cout << fixed << setprecision(6) << result << endl;
    cout << (260 + 220) / (12 + 20) << endl;
    int balance = 100;
    cout << balance << endl;
    balance += 10;
    cout << balance << endl;
    balance -= 20;
    cout << balance << endl;
    balance = 0;
    cout << balance << endl;
    double pi = 3.141593;
    cout << pi * 5 * 2 << endl;
    cout << pi * 5 * 5 << endl;
    cout << pi * (4.0 / 3) * 5 * 5 * 5 << endl;
    cout << (((1 + 1) * 2 + 1) * 2 + 1) * 2 << endl;
    cout << ( ( 10 * 6 )  + ( 10 - 6 ) * (( 8 * 30 - 10 * 6 ) / ( 30 - 6 )) ) / 10 << endl;
    cout << 100 / ( 8 - 5 ) << endl;
    char m = 'M';
    int m_position = m - 'A' + 1;
    std::cout << m_position << std::endl;
    int position = 18;
    char letter = 'A' + position - 1;
    std::cout << letter << std::endl;
    double v1 = (4.0/3.0) * 3.141593 * pow(4, 3);
    double v2 = (4.0/3.0) * 3.141593 * pow(10, 3);
    cout << (int)pow(v1 + v2, 1.0/3.0);
    int a = 1;
    int b = -120;
    int c = 3500;
    int discriminant = b*b - 4*a*c;
    double x1 = (-b + sqrt(discriminant)) / (2*a);
    double x2 = (-b - sqrt(discriminant)) / (2*a);
    int price = min(x1, x2);
    cout << price << endl;
    return 0;
}

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