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P2433【深基1-2】小学数学 N 合一参与者 3已保存回复 9
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CPP
#include<bits/stdc++.h>
using namespace std;
int main(){
cout << "I love luogu!" << endl;
cout << 2 + 4 << " " << 10 - 2 - 4 << endl;
cout << 14 / 4 << endl;
cout << 14 - 14 % 4 << endl;
cout << 14 % 4 << endl;
double result = 500.0 / 3;
cout << fixed << setprecision(6) << result << endl;
cout << (260 + 220) / (12 + 20) << endl;
int balance = 100;
cout << balance << endl;
balance += 10;
cout << balance << endl;
balance -= 20;
cout << balance << endl;
balance = 0;
cout << balance << endl;
double pi = 3.141593;
cout << pi * 5 * 2 << endl;
cout << pi * 5 * 5 << endl;
cout << pi * (4.0 / 3) * 5 * 5 * 5 << endl;
cout << (((1 + 1) * 2 + 1) * 2 + 1) * 2 << endl;
cout << ( ( 10 * 6 ) + ( 10 - 6 ) * (( 8 * 30 - 10 * 6 ) / ( 30 - 6 )) ) / 10 << endl;
cout << 100 / ( 8 - 5 ) << endl;
char m = 'M';
int m_position = m - 'A' + 1;
std::cout << m_position << std::endl;
int position = 18;
char letter = 'A' + position - 1;
std::cout << letter << std::endl;
double v1 = (4.0/3.0) * 3.141593 * pow(4, 3);
double v2 = (4.0/3.0) * 3.141593 * pow(10, 3);
cout << (int)pow(v1 + v2, 1.0/3.0);
int a = 1;
int b = -120;
int c = 3500;
int discriminant = b*b - 4*a*c;
double x1 = (-b + sqrt(discriminant)) / (2*a);
double x2 = (-b - sqrt(discriminant)) / (2*a);
int price = min(x1, x2);
cout << price << endl;
return 0;
}
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