88分求调

#include <stdio.h>
int main()
{
    int requre,a[3],b[3],c[3];
    int i;
    scanf("%d\n",&requre);
    for(i=0;i<3;i++)
    {
        scanf("%d %d\n",&a[i],&b[i]);    
    }
    int j;
    for(j=1;j*a[0]<requre;j++)
     { }   c[0]=j*b[0];
    for(j=1;j*a[1]<requre;j++)
     { }  c[1]=j*b[1];   
    for(j=1;j*a[2]<=requre;j++)
     { } c[2]=j*b[2];
int mid;
  mid = c[0] <= c[1] ? (c[0] <= c[2] ? c[0] : c[2]) : (c[1] <= c[2] ? c[1] : c[2]);
    printf("%d",mid);

    return 0;
}