80求条必关

#include<bits/stdc++.h>
using namespace std;
int main(){
	int n;
	int ans=0;
	cin>>n;
	int a[1005],b[1005],c[1005];
	for(int i=1;i<=n;i++){
		cin>>a[i]>>b[i]>>c[i];
		for(int j=1;j<=n;j++){
			if(abs(a[i]-a[j])<=5 && abs(b[i]-b[j])<=5 && abs(c[i]-c[j])<=5 && abs(a[i]+b[i]+c[i]-a[j]-b[j]-c[j])<=10 ) ans++;
		}
		ans--;
	}
	cout<<ans;
	return 0;
}