求调必关

#include <bits/stdc++.h>
using namespace std;
int a;
int main(){
    cin>>a;
    int b[a],c[a];
    for(int i=0;i<a;i++){
        cin>>b[i];
        while(b[i]!=0){
            c[i]+=b[i]%10;
            b[i]/=10;
        }
    }
    for(int i=0;i<a;i++){
      if(c[i]==7){
            cout<<"Yes"<<endl;
        }else{
            cout<<"No"<<endl;
        }  
    }
    
    return 0;
}