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95分求调
P3372【模板】线段树 1参与者 3已保存回复 3
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- 此快照首次捕获于
- 2025/11/04 03:05 4 个月前
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- 2025/11/04 03:05 4 个月前
写的线段树代码,打了2000多字节,结果最后一个数据被卡了((⊙﹏⊙)),求助谢啦!!☆⌒(*^-゜)v!!
CPP#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;
typedef long long LL;
const LL MAXN = 1000000 + 10;
LL n, m;
LL a[MAXN], tree[MAXN * 4];
LL lazy[MAXN * 4];
void push_down(LL pos, LL left, LL right) {
if (lazy[pos] != 0) {
LL mid = left + (right - left) / 2;
tree[pos + pos] += lazy[pos] * (mid - left + 1);
lazy[pos + pos] += lazy[pos];
tree[pos + pos + 1] += lazy[pos] * (right - mid);
lazy[pos + pos + 1] += lazy[pos];
lazy[pos] = 0;
}
}
void build(LL pos, LL left, LL right) {
if (left == right) {
tree[pos] = a[left];
return ;
}
LL mid = left + (right - left) / 2;
build(pos + pos, left, mid);
build(pos + pos + 1, mid + 1, right);
tree[pos] = tree[pos + pos + 1] + tree[pos + pos];
}
void updateRange(LL pos, LL left, LL right, LL uleft, LL uright, LL val) {
if (uright < left || uleft > right) return ;
if (uleft <= left && uright >= right) {
tree[pos] += val * (right - left + 1);
lazy[pos] += val;
return ;
}
push_down(pos, left, right);
LL mid = left + (right - left) / 2;
updateRange(pos + pos, left, mid, uleft, uright, val);
updateRange(pos + pos + 1, mid + 1, right, uleft, uright, val);
tree[pos] = tree[pos + pos] + tree[pos + pos + 1];
}
LL queryRange(LL pos, LL left, LL right, LL uleft, LL uright) {
if (uright < left || uleft > right) return 0;
if (uleft <= left && right <= uright) return tree[pos];
push_down(pos, left, right);
LL mid = left + (right - left) / 2;
return queryRange(pos + pos, left, mid, uleft, uright) + queryRange(pos + pos + 1, mid + 1, right, uleft, uright);
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n >> m;
for (LL i = 1; i <= n; ++ i) {
cin >> a[i];
}
build(1, 1, n);
LL op, x, y, k;
for (LL i = 1; i <= m; ++ i) {
cin >> op;
if (op == 1) {
cin >> x >> y >> k;
updateRange(1, 1, n, x, y, k);
} else
if (op == 2) {
cin >> x >> y;
cout << queryRange(1, 1, n, x, y) << "\n";
}
}
return 0;
}
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