Python代码求调

n,x=map(int,input().split())
l=list(map(int,input().split()));sumn=0
eat=[l[i]+l[i-1]-x for i in range(1,n)]+[0]
for j in range(n-1):
    if eat[j]>0:
        sumn+=eat[j]
        eat[j+1]-=eat[j]
print(sumn)