20分求调

#include<bits/stdc++.h>
using namespace std;
int a[101][101];

int main(){
    int n,m;
    cin>>n>>m;
    for(int i = 1;i <=n;i++){
    	for(int j = 1;j <= n;j++){
    		char t;
    		cin>>t;
    		if(t == '*') a[i][j] = 1;
		}
	}
	for(int i = 1;i <= n;i++){
		for(int j = 1;j <= m;j++){
			if(a[i][j] == 1) cout<<'*';
			else cout<<a[i-1][j]+a[i+1][j]+a[i][j-1]+a[i][j+1]+a[i-1][j-1]+a[i-1][j+1]+a[i+1][j-1]+a[i+1][j+1];
		}
	}
	return 0;
}