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P6742 水题求调 玄关
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- 此快照首次捕获于
- 2025/11/04 06:44 4 个月前
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- 2025/11/04 06:44 4 个月前
rt,subtask 1~4 AC subtask 5 WA
CPP#include <cstdio>
#include <algorithm>
#include <queue>
#include <vector>
#include <cstring>
using namespace std;
typedef int LL;
const LL N = 1010, M = 1000010;
LL n, m, s, t;
LL dx[5] = {0, 1, 0, -1, 0}, dy[5] = {0, 0, 1, 0, -1};
struct nod{
LL x, y;
inline friend bool operator <(const nod &x, const nod &y) {
return x.y > y.y;
}
};
LL b[N][N], d[N][N], dis[M], vis[M];
vector<pair<LL, LL>> a[M];
priority_queue<nod> q;
int main() {
memset(d, 0x3f, sizeof(d));
memset(dis, 0x3f, sizeof(dis));
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; i++) {
getchar();
for (int j = 1; j <= m; j++) {
char c;
c = getchar();
if (c == '.') b[i][j] = 0;
if (c == '#') b[i][j] = 1;
if (c == 'S') {
b[i][j] = 0;
s = i * m + j;
}
if (c == 'C') {
b[i][j] = 0;
t = i * m + j;
}
}
}
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
if (b[i][j]) continue;
for (int k = 1; k <= 4; k++) {
LL nx = i + dx[k];
LL ny = j + dy[k];
if (nx <= 0 || nx >= n + 1 || ny <= 0 || ny >= m + 1 || b[nx][ny]) continue;
LL nz = nx * m + ny;
LL z = i * m + j;
a[z].push_back({nz, 1});
}
}
}
for (int i = 1; i <= n; i++) {
LL tmp = -1;
for (int j = 1; j <= m; j++) {
if (b[i][j]) { tmp = -1; continue; }
if (tmp == -1) tmp = j;
d[i][j] = min(d[i][j], j - tmp + 1);
}
}
for (int i = 1; i <= n; i++) {
LL tmp = -1;
for (int j = m; j >= 1; j--) {
if (b[i][j]) { tmp = -1; continue; }
if (tmp == -1) tmp = j;
d[i][j] = min(d[i][j], tmp - j + 1);
}
}
for (int j = 1; j <= m; j++) {
LL tmp = -1;
for (int i = 1; i <= n; i++) {
if (b[i][j]) { tmp = -1; continue; }
if (tmp == -1) tmp = i;
d[i][j] = min(d[i][j], i - tmp + 1);
}
}
for (int j = 1; j <= m; j++) {
LL tmp = -1;
for (int i = n; i >= 1; i--) {
if (b[i][j]) { tmp = -1; continue; }
if (tmp == -1) tmp = i;
d[i][j] = min(d[i][j], tmp - i + 1);
}
}
for (int i = 1; i <= n; i++) {
LL tmp = -1;
for (int j = 1; j <= m; j++) {
if (b[i][j]) { tmp = -1; continue; }
if (tmp == -1) tmp = j;
a[i * m + j].push_back({i * m + tmp, min(d[i][j], j - tmp)});
}
}
for (int i = 1; i <= n; i++) {
LL tmp = -1;
for (int j = m; j >= 1; j--) {
if (b[i][j]) { tmp = -1; continue; }
if (tmp == -1) tmp = j;
a[i * m + j].push_back({i * m + tmp, min(d[i][j], tmp - j)});
}
}
for (int j = 1; j <= m; j++) {
LL tmp = -1;
for (int i = 1; i <= n; i++) {
if (b[i][j]) { tmp = -1; continue; }
if (tmp == -1) tmp = i;
a[i * m + j].push_back({tmp * m + j, min(d[i][j], i - tmp)});
}
}
for (int j = 1; j <= m; j++) {
LL tmp = -1;
for (int i = n; i >= 1; i--) {
if (b[i][j]) { tmp = -1; continue; }
if (tmp == -1) tmp = i;
a[i * m + j].push_back({tmp * m + j, min(d[i][j], tmp - i)});
}
}
dis[s] = 0;
q.push({s, dis[s]});
while (q.size()) {
nod prz = q.top();
q.pop();
if (vis[prz.x]) continue;
vis[prz.x] = 1;
for (pair<LL, LL> tmp : a[prz.x]) {
if (vis[tmp.first]) continue;
if (dis[tmp.first] > dis[prz.x] + tmp.second) {
dis[tmp.first] = dis[prz.x] + tmp.second;
q.push({tmp.first, dis[tmp.first]});
}
}
}
printf("%d\n", dis[t]);
}
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