21tps求条

#include<bits/stdc++.h>
using namespace std;
const int N=10000;
int n,k;
double a[N];
bool check(int x){
    int sum=0;
    for(int i=1;i<=n;++i) sum+=a[i]/x;
    return sum>=k;
}
int main(){
    scanf("%d%d",&n,&k);
    for(int i=1;i<=n;++i) scanf("%lf",&a[i]);
    double l=0.00,r=100000.00;
    while(r-l>1e-6){
        double mid=(r+l)/2;
        if(check(mid)) l=mid;
        else r=mid;
    }
    printf("%.2lf",l);
    return 0;
}