社区讨论
站外题求hack or debug
灌水区参与者 1已保存回复 0
讨论操作
快速查看讨论及其快照的属性,并进行相关操作。
- 当前回复
- 0 条
- 当前快照
- 1 份
- 快照标识符
- @m6uizmxa
- 此快照首次捕获于
- 2025/02/07 16:49 去年
- 此快照最后确认于
- 2025/11/04 09:48 4 个月前
玄关
题目:悲剧文本
CPPYou’re typing a long text with a broken keyboard. Well it’s not so badly broken. The only problem
with the keyboard is that sometimes the “home” key or the “end” key gets automatically pressed
(internally).
You’re not aware of this issue, since you’re focusing on the text and did not even turn on the
monitor! After you finished typing, you can see a text on the screen (if you turn on the monitor).
In Chinese, we can call it Beiju. Your task is to find the Beiju text.
Input
There are several test cases. Each test case is a single line containing at least one and at most 100,000
letters, underscores and two special characters ‘[’ and ‘]’. ‘[’ means the “Home” key is pressed
internally, and ‘]’ means the “End” key is pressed internally. The input is terminated by end-of-file
(EOF).
Output
For each case, print the Beiju text on the screen.
Sample Input
This_is_a_[Beiju]_text
[[]][][]Happy_Birthday_to_Tsinghua_University
Sample Output
BeijuThis_is_a__text
Happy_Birthday_to_Tsinghua_University
代码:
CPP#include<bits/stdc++.h>
using namespace std;
string str;
char arr[100050];
int nxt[100050];
int main()
{
while(cin>>str)
{
int len=str.length();
int ptr=0;
int last=0;
int blank=2;
nxt[0]=1;
for(int i=0;i<len;i++)
{
if(str[i]=='[')
{
ptr=0;
}
else if(str[i]==']')
{
ptr=last;
}
else
{
nxt[blank]=nxt[ptr];
nxt[ptr]=blank;
arr[blank]=str[i];
blank++;
if(ptr==last)
{
last=nxt[ptr];
}
ptr=nxt[ptr];
}
}
int tmp=0;
while(tmp!=1)
{
cout<<arr[nxt[tmp]];
tmp=nxt[tmp];
}
cout<<endl;
}
return 0;
}
回复
共 0 条回复,欢迎继续交流。
正在加载回复...