90分

#include<bits/stdc++.h>
using namespace std;
long long a[50090],b[59000];
int main()
{
    long long n,m,k;
    cin>>k>>m>>n;
    bool f=false;
    for(long long i=1;i<=m;i++)
    {
        cin>>a[i]>>b[i];
        if(a[i]==0&&b[i]>0){cout<<i<<" ";f=false;}
        else if(k/a[i]*b[i]>n){cout<<i<<" ";f=true;}
    }
    if(f==false)cout<<-1;
    return 0;
}