社区讨论
编译器，可找语法错误或编译成c++或输入n输出结果
P10400『STA - R5』消失的计算机参与者 2已保存回复 1
讨论操作
快速查看讨论及其快照的属性，并进行相关操作。
- 当前回复
- 1 条
- 当前快照
- 1 份
- 快照标识符
- @m3zwm4js
- 此快照首次捕获于
- 2024/11/27 21:10 去年
- 此快照最后确认于
- 2025/11/04 13:47 4 个月前
大佬若找到代码的bug，可以在该帖子发布，作者定期查看。编译成c++可用while或do while。
①while:使用while编译出的c++代码较长，代码较长或循环较多的不建议编译成while形式。
②do while:使用do while的话一定要保证循环不交叉（可嵌套），循环交叉样例如下：
CPP(此代码无实际意义)
new 2
dec 3
ifneq 2 1 goto 1
new 4
ifneq 4 1 goto 2
图示如下
← ← ←
↓ ↑
1 2 3 4 5
↑ ↓
← ← ← ←
这里面第一个循环和第二个循环交叉，交叉部分为第2，3条语句，所以不能编译成do while形式，只能编译成while形式（所有代码均可转化为while形式）
代码如下，此代码还能找到你的语法错误或者输入n运行
CPP#include<bits/stdc++.h>
using namespace std;
int a,n,v[1001],x[1001],y[1001],l[1001],p[1001],wrong;
string z[1001];
void kg(int tab){
for(int i=1;i<=tab;i++)cout<<" ";
}void lll(int l1,int r,int tab){
for(int i=l1;i<=r;i++){
if(v[i]==1){
kg(tab);
cout<<"n++;\n";
kg(tab);
cout<<"p["<<x[i]<<"]=n;\n";
}if(v[i]==2){
kg(tab);
cout<<"p["<<x[i]<<"]--;\n";
}if(v[i]==3){
kg(tab);
cout<<"p["<<x[i]<<"]=p["<<y[i]<<"];\n";
}if(v[i]==4){
kg(tab);
cout<<"while(p["<<x[i]<<"]>=0){\n";
lll(l[i],i-1,tab+1);
kg(tab);
cout<<"}\n";
}if(v[i]==5){
kg(tab);
cout<<"while(p["<<x[i]<<"]==p["<<y[i]<<"]){\n";
lll(l[i],i-1,tab+1);
kg(tab);
cout<<"}\n";
}if(v[i]==6){
kg(tab);
cout<<"while(p["<<x[i]<<"]!=p["<<y[i]<<"]){\n";
lll(l[i],i-1,tab+1);
kg(tab);
cout<<"}\n";
}
}
}void llll(int l1,int r,int tab){
for(int i=l1;i<=r;i++){
for(int j=r;j>=l1+1;j--){
if(l[j]==i)kg(tab),cout<<"do{\n",tab++;
}if(v[i]==1){
kg(tab);
cout<<"n++;\n";
kg(tab);
cout<<"p["<<x[i]<<"]=n;\n";
}if(v[i]==2){
kg(tab);
cout<<"p["<<x[i]<<"]--;\n";
}if(v[i]==3){
kg(tab);
cout<<"p["<<x[i]<<"]=p["<<y[i]<<"];\n";
}if(v[i]==4){
tab--;
kg(tab);
cout<<"}while(p["<<x[i]<<"]>=0);\n";
}if(v[i]==5){
tab--;
kg(tab);
cout<<"}while(p["<<x[i]<<"]==p["<<y[i]<<"]);\n";
}if(v[i]==6){
tab--;
kg(tab);
cout<<"}while(p["<<x[i]<<"]!=p["<<y[i]<<"]);\n";
}
}
}
int main(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin>>a;
cin.ignore();
for(int i=1;i<=a;i++)getline(cin,z[i]);
for(int i=1;i<=a;i++){
int shu=0,c=0,d=1;
string b;
for(int j=0;j<=z[i].size();j++){
if(z[i].size()==0||!v[i]&&b==""&&z[i].size()==j){
cout<<"错误"<<++wrong<<"：第"<<i<<"行："<<"不可以是空串或全是空格\n";
}
if(z[i][j]==' '||j==z[i].size()){
if(c==0&&b.size()==0)continue;
if(b==""&&!v[i])continue;
if(!v[i]){
if(b=="new")v[i]=1;
else if(b=="dec")v[i]=2;
else if(b=="assign")v[i]=3;
else if(b=="iftry")v[i]=4;
else if(b=="ifeq")v[i]=5;
else if(b=="ifneq")v[i]=6;
else {
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：没有"<<b<<"这个语法\n";
break;
}
}if(v[i]==4&&shu==1||v[i]==5&&shu==2||v[i]==6&&shu==2){
if(b!="goto"){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列："<<b<<"应为goto\n";
break;
}shu++;
}if(v[i]){
if(c>0)shu++;
if(v[i]==1){
if(c>1000){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
break;
}if(shu!=1&&j==z[i].size()){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：new 语法的格式应为 new x\n";
break;
}x[i]=c;
}else if(v[i]==2){
if(c>1000){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
break;
}if(shu!=1&&j==z[i].size()){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：dec 语法的格式应为 dec x\n";
break;
}x[i]=c;
}else if(v[i]==3){
if(c>1000){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
break;
}if(shu!=2&&j==z[i].size()){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：assign 语法的格式应为 assign x y\n";
break;
}if(shu==1)x[i]=c;
if(shu==2)y[i]=c;
}else if(v[i]==4){
if(shu!=3&&j==z[i].size()){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：iftry 语法的格式应为 iftry x y goto l\n";
break;
}
if(shu==3&&c>=i){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：l应小于当前条数"<<i<<"\n";
break;
}else{
if(c>1000){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
break;
}
}if(shu==1)x[i]=c;
if(shu==3)l[i]=c;
}else if(v[i]==5){
if(shu!=4&&j==z[i].size()){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：ifeq 语法的格式应为 ifeq x y goto l\n";
break;
}
if(shu==4&&c>=i){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：l应小于当前条数"<<i<<"\n";
break;
}else{
if(c>1000){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
break;
}
}if(shu==1)x[i]=c;
if(shu==2)y[i]=c;
if(shu==4)l[i]=c;
}else if(v[i]==6){
if(shu!=4&&j==z[i].size()){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：ifneq 语法的格式应为 ifneq x y goto l\n";
break;
}
if(shu==4&&c>=i){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：l应小于当前条数"<<i<<"\n";
break;
}else{
if(c>1000){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<d<<"列：变量只有1000个\n";
break;
}
}if(shu==1)x[i]=c;
if(shu==2)y[i]=c;
if(shu==4)l[i]=c;
}
}
c=0;
b="";
d=j+2;
}else if(v[i]==0||v[i]==4&&shu==1||v[i]==5&&shu==2||v[i]==6&&shu==2)b+=z[i][j];
else {
if(c==0&&z[i][j]=='0'){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<j<<"列：数字开头不能为0/数字不能为0\n";
break;
}if(z[i][j]>'9'||z[i][j]<'0'){
cout<<"错误"<<++wrong<<"：第"<<i<<"行：第"<<j<<"列：数字中不能出现不是数字的字符\n";
break;
}c=c*10+z[i][j]-48;
}
}
}
if(wrong)return 0;
printf("编译成功\n");
printf("请输入n，或输入0编译成c++ while形式，输入1编译成c++ do while形式（需要保证没有交叉循环（不代表不能用嵌套），否则编译出的c++代码会错误）\n");
while(1){
cin>>n;
if(n<=100&&n>=5||n==0||n==1)break;
printf("5<=n<=100，请重输\n");
}
if(n==0){
cout<<"#include<bits/stdc++.h>\n";
cout<<"using namespace std;\n";
cout<<"int p[1001],n;\n";
cout<<"int main(){\n";
cout<<" cout<<"<<'"'<<"请输入n\\n"<<'"'<<";\n";
cout<<" cin>>n;\n";
cout<<" p[1]=n;\n";
lll(1,a,1);
cout<<" cout<<"<<'"'<<"输出的结果是"<<'"'<<"<<n;\n";
cout<<" return 0;\n";
cout<<"}";
return 0;
}if(n==1){
cout<<"#include<bits/stdc++.h>\n";
cout<<"using namespace std;\n";
cout<<"int p[1001],n;\n";
cout<<"int main(){\n";
cout<<" cout<<"<<'"'<<"请输入n\\n"<<'"'<<";\n";
cout<<" cin>>n;\n";
cout<<" p[1]=n;\n";
llll(1,a,1);
cout<<" cout<<"<<'"'<<"输出的结果是"<<'"'<<"<<n;\n";
cout<<" return 0;\n";
cout<<"}";
return 0;
}
int mm=0;
p[1]=n;
for(int i=1;i<=a;){
mm++;
if(mm>100000){
printf("运行次数超过100000次，或进入死循环");
return 0;
}if(v[i]==1)n++,p[x[i]]=n,i++;
else if(v[i]==2)p[x[i]]--,i++;
else if(v[i]==3)p[x[i]]=p[y[i]],i++;
else if(v[i]==4){
if(p[x[i]]>=0)i=l[i];
else i++;
continue;
}else if(v[i]==5){
if(p[x[i]]==p[y[i]])i=l[i];
else i++;
continue;
}else if(v[i]==6){
if(p[x[i]]!=p[y[i]])i=l[i];
else i++;
continue;
}
}printf("输出的结果是：%d\n",n);
if(a>1000){
printf("条数大于1000条，请寻找更优解\n");
return 0;
}
return 0;
}
MattL感谢反馈，已改正错误。
回复
共 1 条回复，欢迎继续交流。
正在加载回复...