对于B4045的数据

#include<bits/stdc++.h>
using namespace std;
#define int long long
int s[10000001];
signed main(){
	int n;
	cin>>n;
	int ans=n;
	int k,d,a;
	for(int i=1;i<=n;i++){
		scanf("%d/%d/%d",&k,&d,&a);
		if(k-d>=10) s[i]=k*(k-d)+a;
		else if(k>=d) s[i]=(k-d+1)*3-1;
		else s[i]=a*2;
	}
	for(int i=1;i<=n;i++){
		if(s[i]>s[ans]){
			ans=i;
		}
	}
	cout<<ans;
	return 0;
}