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2025.9.7 正睿 NOIP模拟赛2 T4

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f0,n,mf'_{0,n,m} 表示双连通图点数 nn 边数 mm 的方案数
f0,n,mf_{0,n,m} 表示双连通图点数 nn 边数 mm 的权值和
gx,n,mg'_{x,n,m} 表示连通图点数 n+xn+x 边数 mm 树根点数 xx 的方案数
gx,n,mg_{x,n,m} 表示连通图点数 n+xn+x 边数 mm 树根点数 xx 的权值和
hn,mh'_{n,m} 表示一般图点数 nn 边数 mm 的方案数
hn,mh_{n,m} 表示一般图点数 nn 边数 mm 的权值和
f0,n,m=Ci+12f0,n,m1+12f1,n,m1f'_{0,n,m} = C_{i+1}^{2} f'_{0,n,m-1} + \frac{1}{2}f'_{1,n,m-1}
f1,n,m=CniCmj(mj)×i2×f0,i,jf0,ni,mj1×(ni)2+CniCmj(mj)×i2×f0,i,jf1,ni,mj1\begin{aligned} f'_{1,n,m} &= C_n^i C_m^j (m-j) \times i^2 \times f'_{0,i,j}f'_{0,n-i,m-j-1} \times (n-i)^2 \\ &+ C_n^i C_m^j (m-j) \times i^2 \times f'_{0,i,j}f'_{1,n-i,m-j-1} \end{aligned}
f0,n,m=Ci+12f0,n,m1+Ci+12f0,n,m1B+12f1,n,m1f_{0,n,m} = C_{i+1}^{2} f_{0,n,m-1} + C_{i+1}^{2}f'_{0,n,m-1}B + \frac{1}{2}f_{1,n,m-1}
f1,n,m1=CniCmj(mj)×i2×f0,i,jf0,ni,mj1×(ni)2+CniCmj(mj)×i2×f0,i,jf0,ni,mj1×(ni)2+CniCmj(mj)×i2×f0,i,jf1,ni,mj1+CniCmj(mj)×i2×f0,i,jf1,ni,mj1+CniCmj(mj)×i2×f0,i,jf0,ni,mj1×(ni)2×A+CniCmj(mj)×i2×f0,i,jf1,ni,mj1×A\begin{aligned} f_{1,n,m-1} &= C_n^i C_m^j (m-j) \times i^2 \times f'_{0,i,j}f_{0,n-i,m-j-1} \times (n-i)^2 \\ &+ C_n^i C_m^j (m-j) \times i^2 \times f_{0,i,j}f'_{0,n-i,m-j-1} \times (n-i)^2 \\ &+ C_n^i C_m^j (m-j) \times i^2 \times f'_{0,i,j}f_{1,n-i,m-j-1} \\ &+ C_n^i C_m^j (m-j) \times i^2 \times f_{0,i,j}f'_{1,n-i,m-j-1} \\ &+ C_n^i C_m^j (m-j) \times i^2 \times f'_{0,i,j}f'_{0,n-i,m-j-1} \times (n-i)^2 \times A\\ &+ C_n^i C_m^j (m-j) \times i^2 \times f'_{0,i,j}f'_{1,n-i,m-j-1} \times A \end{aligned}
g0,n,m=Cn1i1Cmj×f0,i,jgi,ni,mjg'_{0,n,m} = C_{n-1}^{i-1}C_m^j \times f'_{0,i,j}g'_{i,n-i,m-j}
ga,n,m=Cn1i1Cmj(mj)×g0,i,jga,ni,mj1×aig'_{a,n,m} = C_{n-1}^{i-1}C_m^j(m-j) \times g'_{0,i,j}g'_{a,n-i,m-j-1} \times ai
g0,n,m=Cn1i1Cmj×f0,i,jgi,ni,mj+Cn1i1Cmj×f0,i,jgi,ni,mj\begin{aligned} g_{0,n,m} &= C_{n-1}^{i-1}C_m^j \times f'_{0,i,j}g_{i,n-i,m-j} \\ &+ C_{n-1}^{i-1}C_m^j \times f_{0,i,j}g'_{i,n-i,m-j} \end{aligned}
ga,n,m=Cn1i1Cmj(mj)×g0,i,jga,ni,mj1×ai+Cn1i1Cmj(mj)×g0,i,jga,ni,mj1×ai+Cn1i1Cmj(mj)×g0,i,jga,ni,mj1×ai×A\begin{aligned} g_{a,n,m} &= C_{n-1}^{i-1}C_m^j(m-j) \times g'_{0,i,j}g_{a,n-i,m-j-1} \times ai \\ &+ C_{n-1}^{i-1}C_m^j(m-j) \times g_{0,i,j}g'_{a,n-i,m-j-1} \times ai \\ &+ C_{n-1}^{i-1}C_m^j(m-j) \times g'_{0,i,j}g'_{a,n-i,m-j-1} \times ai \times A \end{aligned}
hn,m=Cn1i1Cmj×g0,i,jhni,mjh'_{n,m} = C_{n-1}^{i-1}C_m^j \times g_{0,i,j}h'_{n-i,m-j}
hn,m=Cn1i1Cmj×g0,i,jhni,mj+Cn1i1Cmj×g0,i,jhni,mj\begin{aligned} h_{n,m} &= C_{n-1}^{i-1}C_m^j \times g'_{0,i,j}h_{n-i,m-j} \\ &+ C_{n-1}^{i-1}C_m^j \times g_{0,i,j}h'_{n-i,m-j} \end{aligned}
(注:“==”实际上是“+=+=” )
f0,1,m=1f_{0,1,m} = 1
ga,0,0=1g_{a,0,0} = 1
h0,0=1h_{0,0} = 1
A=ACA = A - C
B=BCB = B - C
T=1,ans=fn,m+C×m×fn,mT = 1,ans = f_{n,m} + C \times m \times f'_{n,m}
T=2,ans=hn,m+C×m×(Cn+1,2)mT = 2,ans = h'_{n,m} + C \times m \times (C_{n+1,2})^m

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