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- @minyiolt
- 此快照首次捕获于
- 2025/12/02 10:26 3 个月前
- 此快照最后确认于
- 2025/12/02 10:26 3 个月前
CPP
#include<bits/stdc++.h>
typedef long long ll;
using namespace std;
template<typename T> void re(T&x){x = 0; int sign = 1; char c;do{c = getchar(); if (c == '-') sign = -1;}while(!isdigit(c)); do{x = x * 10 + c - '0'; c = getchar();}while(isdigit(c)); x *= sign;}
void write(int x){if (x < 0) x = -x, putchar('-'); if (x < 10) putchar(x + '0'); else write(x / 10), putchar(x % 10 + '0');}
const int N = 2e6 + 100;
struct node{
ll val, r, l, lzy1 = 0, lzy2 = 0;
};
ll n, m;
ll a[N];
node t[N];
void build(ll id, ll l, ll r){
t[id].l = l, t[id].r = r;
if (l == r){
t[id].val = a[l];
return;
}
ll val1, val2;
ll mid = l + r >> 1;
build(id << 1, l, mid);
build(id << 1 | 1, mid + 1, r);
val1 = t[id << 1].val, val2 = t[id << 1 | 1].val;
t[id].val = val1 + val2;
}
void push_down(ll id){
if (t[id].lzy2 == 1){
t[id << 1].lzy2 = t[id << 1 | 1].lzy2 = 1;
t[id << 1].lzy1 = t[id << 1 | 1].lzy1 = 0;
t[id << 1].val = t[id << 1 | 1].val = 0;
t[id].lzy2 = 0;
}
if (t[id].lzy1 != 0){
t[id << 1].lzy1 += t[id].lzy1;
t[id << 1 | 1].lzy1 += t[id].lzy1;
t[id << 1].val = t[id].lzy1 * (t[id << 1].r - t[id << 1].l + 1);
t[id << 1 | 1].val = t[id].lzy1 * (t[id << 1 | 1].r - t[id << 1 | 1].l + 1);
t[id].lzy1 = 0;
}
}
void add(ll id, ll l, ll r, ll L, ll R, ll pos){
if (L == l && R == r){
t[id].val = t[id].val + (r - l + 1) * pos;
t[id].lzy1 += pos;
return;
}
push_down(id);
ll mid = l + r >> 1;
ll val1, val2;
if (R <= mid) add(id << 1, l, mid, L, R, pos);
else if (L > mid) add(id << 1 | 1, mid + 1, r, L, R, pos);
else add(id << 1, l, mid, L, mid, pos), add(id << 1 | 1, mid + 1, r, mid + 1, R, pos);
val1 = t[id << 1].val, val2 = t[id << 1 | 1].val;
t[id].val = val1 + val2;
}
void gui0(ll id, ll l, ll r, ll L, ll R){
if (l == L && r == R){
t[id].val = 0;
t[id].lzy1 = 0;
t[id].lzy2 = 1;
return;
}
push_down(id);
ll mid = l + r >> 1;
ll val1, val2;
if (R <= mid) gui0(id << 1, l, mid, L, R);
else if (L > mid) gui0(id << 1 | 1, mid + 1, r, L, R);
else gui0(id << 1, l, mid, L, mid), gui0(id << 1 | 1,mid + 1, r, mid + 1, R);
val1 = t[id << 1].val, val2 = t[id << 1 | 1].val;
t[id].val = val1 + val2;
}
ll find(ll id, ll l, ll r, ll L, ll R){
if (l == L && r == R){
return t[id].val;
}
push_down(id);
ll mid = l + r >> 1;
ll val1, val2;
if (R <= mid) return find(id << 1, l, mid, L, R);
else if (L > mid) return find(id << 1 | 1, mid + 1, r, L, R);
else return find(id << 1, l, mid, L, mid) + find(id << 1 | 1, mid + 1, r, mid + 1, R);
val1 = t[id << 1].val, val2 = t[id << 1 | 1].val;
t[id].val = val1 + val2;
}
int main(){
// freopen("2.in", "r", stdin);
// freopen("2.out", "w", stdout);
re(n), re(m);
for (int i = 1; i <= n; i ++){
re(a[i]);
}
build(1, 1, n);
ll op, l, r, x;
while (m --){
re(op), re(l), re(r);
if (op == 1){
re(x);
add(1, 1, n, l, r, x);
}
if (op == 2){
re(x);
add(1, 1, n, l, r, -x);
}
if (op == 3){
gui0(1, 1, n, l, r);
}
if (op == 4){
printf("%lld\n", find(1, 1, n, l, r));
}
}
return 0;
}
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