题解：P5730 【深基5.例10】显示屏

思路：

给你一串数字，请输出其对应的

3 \times 5

的点阵。

~~联系生活实际，做过电梯的都懂。~~

由于每个数字对应的点阵是固定的，因此本题可以使用贪心 $+$ 暴力解决。只需将

0 \sim 9

中的所有整数的点阵存入数组，需要时再调用即可。

Code:

CPP

#include<bits/stdc++.h>
using namespace std;
int n;
string s;
string ans[10][5]={"XXX","X.X","X.X","X.X","XXX",
				  	 "..X","..X","..X","..X","..X",
				 	 "XXX","..X","XXX","X..","XXX",
				   	 "XXX","..X","XXX","..X","XXX",
				   	 "X.X","X.X","XXX","..X","..X",
				   	 "XXX","X..","XXX","..X","XXX",
				  	 "XXX","X..","XXX","X.X","XXX",
				   	 "XXX","..X","..X","..X","..X",
				  	 "XXX","X.X","XXX","X.X","XXX",
				  	 "XXX","X.X","XXX","..X","XXX"};
//ans数组存0~9中整数相对应的点阵。
int main(){
	cin>>n>>s;
	for(int i=0;i<5;i++){//5行。
		for(int j=0;j<n;j++){//n列。
			cout<<ans[s[j]-'0'][i];//输出对应点阵。
			if(j!=n-1)cout<<".";//输出间隔符。
		}
		cout<<"\n";//换行。
	}
	return 0;//好习惯。
}

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题解：P5730 【深基5.例10】显示屏

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题解：P5730 【深基5.例10】显示屏