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第四天作业
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- 此快照首次捕获于
- 2025/12/03 02:47 3 个月前
- 此快照最后确认于
- 2025/12/03 02:47 3 个月前
第一题
CPP#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cmath>
#include<cstring>
using namespace std;
struct node{
int l,r;
}a[1001000];//记录每个节点的左右节点
int Max=-1,n;
void dfs(int root,int step){
if(root==0) return;//如果该节点为0(即上它的爸爸没有这个儿子),返回
Max=max(Max,step);//记录最大值
dfs(a[root].l,step+1);//搜索它的左儿子
dfs(a[root].r,step+1);//搜索它的右儿子
}
int main(){
cin>>n;//输入n
for(int i=1;i<=n;i++){
cin>>a[i].l>>a[i].r;//输入该节点的左节点和右节点
}
dfs(1,1);//从1号节点,深度为1开始搜索
cout<<Max;//输出最大值
return 0;
}
第二题
CPP#include <iostream>
#include <vector>
using namespace std;
void dfs(int node, vector<vector<int>>& children, vector<int>& subtree_size) {
for (int child : children[node]) {
dfs(child, children, subtree_size);
subtree_size[node] += subtree_size[child];
}
}
int main() {
int n;
cin >> n;
vector<vector<int>> children(n + 1);
for (int i = 2; i <= n; ++i) {
int parent;
cin >> parent;
children[parent].push_back(i);
}
vector<int> subtree_size(n + 1, 1);
dfs(1, children, subtree_size);
for (int i = 1; i <= n; ++i) {
cout << subtree_size[i] << endl;
}
return 0;
}
第三题
CPP#include<bits/stdc++.h>
using namespace std;
const int maxn=1005;
vector<int> c[maxn];
int weight[maxn];
int sum[maxn];
int n;
void dfs(int node) {
sum[node] = weight[node];
for(int i=0; i<c[node].size(); i++) {
int child = c[node][i];
dfs(child);
sum[node] += sum[child];
}
}
int main() {
cin >> n;
for(int i=1; i<=n; i++) {
int f, w;
cin >> f >> w;
weight[i] = w;
if(f != 0) {
c[f].push_back(i);
}
}
dfs(1);
for(int i=1; i<=n; i++) {
cout << sum[i] << endl;
}
return 0;
}
第四题
CPP#include<iostream>
#define ll long long
using namespace std;
void dfs(ll i,ll x,ll n){
if(x == 1){
return;
}
if(i*i>n){
if(x>1){
cout<<x;
}
return ;
}
while(x%i==0){
x/=i;
cout<<i;
}
dfs(i+1,x,n);
}
int main(){
int t;
cin>>t;
while(t--){
ll n;
cin>>n;
dfs(2,n,n);
cout<<endl;
}
return 0;
}
第五题
CPP#include<bits/stdc++.h>
using namespace std;
vector <int> g[123456];
bool vis[123456];
int ans,n,d;
void dfs(int now,int dis)
{
vis[now]=1;
if(dis==d) return;
for(int i=0;i<g[now].size();i++)
{
if(!vis[g[now][i]])
{
dfs(g[now][i],dis+1);
ans++;
}
}
}
int main()
{
cin>>n>>d;
for(int i=1;i<n;i++)
{
int a,b;
cin>>a>>b;
g[a].push_back(b);
g[b].push_back(a);
}
dfs(1,0);
cout<<ans;
return 0;
}
第六题
CPP#include <iostream>
#include <vector>
#include <queue>
using namespace std;
int main() {
int n, m;
cin >> n >> m;
vector<string> maze(n);
for (int i = 0; i < n; i++) {
cin >> maze[i];
}
int dx[4] = {-1, 1, 0, 0};
int dy[4] = {0, 0, -1, 1};
vector<vector<bool>> visited(n, vector<bool>(m, false));
queue<pair<int, int>> q;
q.push({0, 0});
visited[0][0] = true;
while (!q.empty()) {
int x = q.front().first;
int y = q.front().second;
q.pop();
if (x == n - 1 && y == m - 1) {
cout << "Yes" << endl;
return 0;
}
for (int i = 0; i < 4; i++) {
int nx = x + dx[i];
int ny = y + dy[i];
if (nx >= 0 && nx < n && ny >= 0 && ny < m && maze[nx][ny] == '.' && !visited[nx][ny]) {
visited[nx][ny] = true;
q.push({nx, ny});
}
}
}
cout << "No" << endl;
return 0;
}
第七题
CPP#include<iostream>
using namespace std;
int dx[8] = {-1, -1, -1, 0, 0, 1, 1, 1};
int dy[8] = {-1, 0, 1, -1, 1, -1, 0, 1};
int n, m;
char grid[105][105];
void dfs(int x, int y) {
grid[x][y] = '.';
for (int i = 0; i < 8; i++) {
int xa = x + dx[i];
int ya = y + dy[i];
if (xa >= 1 && xa <= n && ya >= 1 && ya <= m && grid[xa][ya] == 'W') {
dfs(xa, ya);
}
}
}
int main() {
cin >> n >> m;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
cin >> grid[i][j];
}
}
int ans = 0;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
if (grid[i][j] == 'W') {
ans++;
dfs(i, j);
}
}
}
cout << ans << endl;
return 0;
}
第八题
CPP#include<iostream>
using namespace std;
int n,m,t,sx,sy,fx,fy,vis[1000][1000],ans;
int dx[]={0,0,-1,1},dy[]={-1,1,0,0};
void dfs(int x,int y){
if(x==fx&&y==fy){
ans++;
return;
}
for(int i=0;i<4;i++){
int xa=x+dx[i],ya=y+dy[i];
if(vis[xa][ya]==0&&xa<=n&&xa>0&&ya<=m&&ya>0){
vis[xa][ya]=1;
dfs(xa,ya);
vis[xa][ya]=0;
}
}
}
int main(){
cin>>n>>m>>t>>sx>>sy>>fx>>fy;
for(int i=0,x,y;i<t;i++){
cin>>x>>y;
vis[x][y]=1;
}
vis[sx][sy]=1;
dfs(sx,sy);
cout<<ans;
return 0;
}
第九题
CPP#include <iostream>
#include <vector>
using namespace std;
void dfs(int n, int k, vector<int>& path, vector<bool>& used) {
if (path.size() == k) {
for (int num : path) {
cout << num << " ";
}
cout << endl;
return;
}
for (int i = 1; i <= n; ++i) {
if (!used[i]) {
used[i] = true;
path.push_back(i);
dfs(n, k, path, used);
path.pop_back();
used[i] = false;
}
}
}
int main() {
int n, k;
cin >> n >> k;
vector<int> path;
vector<bool> used(n + 1, false);
dfs(n, k, path, used);
return 0;
}
第十题
CPP#include <iostream>
using namespace std;
int n, m;
int arr[25]; // 存储当前组合
void dfs(int start, int depth) {
// 如果已经选择了m个数,输出当前组合
if (depth == m) {
for (int i = 0; i < m; i++) {
cout << arr[i];
if (i < m - 1) cout << " ";
}
cout << endl;
return;
}
// 从start到n枚举下一个数
for (int i = start; i <= n; i++) {
arr[depth] = i; // 选择当前数
dfs(i + 1, depth + 1); // 递归选择下一个数
}
}
int main() {
cin >> n >> m; // 输入n和m
dfs(1, 0); // 从1开始深度优先搜索
return 0;
}
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