Fear of the Dark

#include<bits/stdc++.h>
using namespace std;
int T,px,py,ax,ay,bx,by;
double ss(int px,int py,int nx,int ny){//用勾股定理求两点距离 
	int x=px-nx,y=py-ny;
	return sqrtl(x*x+y*y);
}
double solve1(int x,int y){//第一种情况 
	double s1=ss(x,y,px,py); 
	double s2=ss(x,y,0,0);
	return max(s1,s2);
}
double solve2(int ax,int ay,int bx,int by){//第二种情况 
	double s1=ss(ax,ay,0,0); 
	double s2=ss(bx,by,px,py);
	double s3=ss(ax,ay,bx,by)/double(2.0);//要让两个圆相交 
	return max(s1,max(s2,s3));
}
int main(){
	cin>>T;
	while(T--){
		cin>>px>>py>>ax>>ay>>bx>>by;
		//注意：无法确定两个灯笼的位置，所以两种情况要互换灯笼位置 
		double ans1=min(solve1(ax,ay),solve1(bx,by));
		double ans2=min(solve2(ax,ay,bx,by),solve2(bx,by,ax,ay));
		printf("%.10lf\n",min(ans1,ans2));
	}
	return 0;
}