专栏文章

回忆

算法·理论参与者 1已保存评论 0

文章操作

快速查看文章及其快照的属性,并进行相关操作。

当前评论
0 条
当前快照
1 份
快照标识符
@min6z6aq
此快照首次捕获于
2025/12/01 21:35
3 个月前
此快照最后确认于
2025/12/01 21:35
3 个月前
查看原文
CPP
#include <algorithm>
#include <cstddef>
#include <iostream>
#include <vector>
using namespace std;

long long comb(int w, int i) {
    if (i < 0 || i > w) {
        return 0;
    }
    long long res = 1;
    for (int t = 1; t <= i; ++t) {
        res = res * (w - t + 1) / t;
    }
    return res;
}

// 计算长度为 w、1 的个数 ≤k 的码字总数 
long long count_patterns(int w, int k) {
    long long total = 0;
    for (int t = 0; t <= min(w, k); ++t) {
        total += comb(w, t);
    }
    return total;
}

// 抽象测试接口 
int test_subset(const vector<vector<int>>& plan);

int solve(int n, int k) {
	// === 第 1 步:求最小 w === 
    int w = 1;
    while (  ① ) { 
        ++w;
    }
    cout << w << endl;
    
    // === 第 2 步:生成测试方案 === 
    vector<vector<int>> code(n, vector<int>(w, 0));
    int idx = 0;
    for (int ones = 0; ones <= k && idx < n; ++ones) {
        vector<int> bits(w, 0);
        fill(bits.begin(), bits.begin() + ones, 1);
        do {
            for (int b = 0; b < w; ++b) {
                code[idx][b] = bits[b];
            }
            ++idx;
            if (idx >= n) {
                break;
            }
        } while ( std::  ② );
    }
    
    vector<vector<int>> plan(w);
    for (int i = 0; i < w; ++i) {
        for (int j = 0; j < n; ++j) {
            if (  ③ ) { 
                plan[i].push_back(j);
            }
        }
    }
    
    // === 第 3 步:调用测试接口 === 
    int signature = test_subset(plan);
    
    // === 第 4 步:结果解码 === 
    vector<int> sig_bits(w, 0);
    for (int i = 0; i < w; ++i) {
        if (  ④ ) { 
            sig_bits[i] = 1;
        }
    }
    
    for (int j = 0; j < n; ++j) {
        if (  ⑤ ) return j;
    }
}

int main() {
    int n, k;
    cin >> n >> k;
    int ans = solve(n, k);
    cout << ans << endl;
    return 0;
}



#include <algorithm>
#include <iostream>
#include <queue>
#include <vector>
using namespace std;

const long long INF = 1e18;

struct Edge {
	int to;
	int weight;
};
 
struct State {
	long long dist;
	int u;
	int used_freebie;//0 for not used, 1 for used
	bool operator>(const State &other) const {
		return dist > other.dist;
	}
};

int main() {
	int n, m, s, t;
	cin >> n >> m >> s >> t;
	
	vector<vector<Edge>> adj(n + 1);
	for (int i = 0; i < m; ++i) {
		int u, v, w;
		cin >> u >> v >> w;
		adj[u].push_back({v, w});
		adj[v].push_back({u, w});
	}
	
	vector<vector<long long>> d(n + 1, vector<long long>(2, INF));
	priority_queue<State, vector<State>, greater<State>> pq;
	
	d[s][0]= 0;
	pq.push({0, s,   ①  });

	while(!pq.empty()) {
		State current =pq.top();
		pq.pop();
		
		long long dist = current.dist;
		int u= current.u;
		int used = current.used_freebie;
		
		if(dist >   ②  ){
			continue;
		}
		
		for (const auto &edge : adj[u]) {
			int v = edge.to;
			int w = edge.weight;
			
			if(d[u][used] + w <   ③  ){
				   ③  = d[u][used] + w;
				pq.push({  ③  , v , used});
			}
		
			if(used == 0){
				if(  ④   < d[v][1]){
					d[v][1] =   ④  ;
					pq.push({d[v][1], v, 1});
				}
			}
		}
	}
	
	cout <<   ⑤   <<  endl;
	return 0;
}



#include <algorithm>
#include <cstdio>
#include <cstring>
#include <vector>
#define ll long long
int n, m;
std::vector<int> k, p;
inline int mpow(int x, int k) {
   int ans = 1;
    for (; k; k = k >> 1, x = x * x) {
        if (k & 1)
            ans = ans * x;
    }
    return ans;
}
std::vector<int> ans1, ans2;
int cnt1, cnt2;
inline void dfs(std::vector<int>& ans, int& cnt, int l, int r, int v) {
    if (l > r) {
        ++cnt;
        ans.push_back(v);
        return;
    }
    for (int i = 1; i <= m; ++i) {
        dfs(ans, cnt, l + 1, r, v + k[l] * mpow(i, p[l]));
    }
    return;
}
std::vector<int> cntans1;
int main() {
    scanf("%d%d", &n, &m);
    k.resize(n + 1);
    p.resize(n + 1);
    for (int i = 1; i <= n; ++i) {
        scanf("%d%d", &k[i], &p[i]);
    }
    dfs(ans1, cnt1, 1, n >> 1, 0);
    dfs(ans2, cnt2, (n >> 1) + 1, n, 0);
    std::sort(ans1.begin(), ans1.end());
    int newcnt1 = 1;
    cntans1.push_back(1);
    for (int i = 1; i < cnt1; ++i) {
        if (ans1[i] == ans1[newcnt1 - 1]) {
            ++cntans1[newcnt1 - 1];
        } else {
            ans1[newcnt1++] = ans1[i];
            cntans1.push_back(1);
        }
    }
    cnt1 = newcnt1;
    std::sort(ans2.begin(), ans2.end());
    int las = 0;
    ll ans = 0;
    for (int i = cnt2 - 1; i >= 0; --i) {
        for (; las < cnt1 && ans1[las] + ans2[i] < 0; ++las)
            ;
        if (las < cnt1 && ans1[las] + ans2[i] == 0)
            ans += cntans1[las];
    }
    printf("%lld\n", ans);
    return 0;
}



#include <algorithm>
#include <cstdio>
#include <cstring>
#define ll long long
int cnt_broken = 0;
int cnt_check = 0;
int n, k;
inline bool check(int h) {
    printf("now check:%d\n", h);
    ++cnt_check;
    if (cnt_broken == 2) {
        printf("You have no egg!\n");
        return false;
    }
    if (h >= k) {
        ++cnt_broken;
        return true;
    } else {
        return false;
    }
}
inline bool assert_ans(int h) {
    if (h == k) {
        printf("You are Right using %d checks\n", cnt_check);
        return true;
    } else {
        printf("Wrong answer!\n");
        return false;
    }
}
inline void guess1(int n) {
    for (int i = 1; i <= n; ++i) {
        if (check(i)) {
            assert_ans(i);
            return;
        }
    }
}
inline void guess2(int n) {
    int w = 0;
    for (w = 1; w * (w + 1) / 2 < n; ++w)
        ;
    for (int ti = w, nh = w;; --ti, nh += ti, nh = std::min(nh, n)) {
        if (check(nh)) {
            for (int j = nh - ti + 1; j < nh; ++j) {
                if (check(j)) {
                    assert_ans(j);
                    return;
                }
            }
            assert_ans(nh);
            return;
        }
    }
}
int main() {
    scanf("%d%d", &n, &k);
    int t;
    scanf("%d", &t);
    if (t == 1) {
        guess1(n);
    } else {
        guess2(n);
    }
    return 0;
}





#include <algorithm>
#include <cstdio>
#include <cstring>
bool flag[27];
int n;
int p[27];
int ans = 0;
void dfs(int k) {
    if (k == n + 1) {
		++ans;
		return;
	}
	for (int i = 1; i <= n; ++i) {
		if (flag[i]) continue;
		if (k > 1 && i == p[k - 1] + 1) continue;
		p[k] = i;
		flag[i] = true;
		dfs(k + 1);
		flag[i] = false;
	}
	return;
}
int main() {
	scanf("%d", &n);
	dfs(1);
	printf("%d\n", ans);
	return 0;
}
YouYou havehave nono egg!egg!

评论

0 条评论,欢迎与作者交流。

正在加载评论...